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gdbstub: Explicitly cast return type to u8
Otherwise, the addition promotes the returned value to an int instead of keeping it as a u8.
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1 changed files with 2 additions and 2 deletions
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@ -358,8 +358,8 @@ std::optional<std::string> GDBStub::DetachCommand() {
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}
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u8 GDBStub::CalculateChecksum(std::string_view data) {
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return static_cast<u8>(
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std::accumulate(data.begin(), data.end(), u8{0}, [](u8 lhs, u8 rhs) { return lhs + rhs; }));
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return std::accumulate(data.begin(), data.end(), u8{0},
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[](u8 lhs, u8 rhs) { return static_cast<u8>(lhs + rhs); });
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}
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void GDBStub::SendReply(std::string_view data) {
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