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string_util: Remove unnecessary std::string instance in TabsToSpaces()

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We can just use the variant of std::string's replace() function that can
replace an occurrence with N copies of the same character, eliminating
the need to allocate a std::string containing a buffer of spaces.
This commit is contained in:
Lioncash 2018-07-22 15:33:07 -04:00
parent c994cdc532
commit cd46b267f5
2 changed files with 7 additions and 8 deletions
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13
src/common/string_util.cpp
View file

@ -168,15 +168,14 @@ void SplitString(const std::string& str, const char delim, std::vector<std::stri
output.pop_back();
}
std::string TabsToSpaces(int tab_size, const std::string& in) {
const std::string spaces(tab_size, ' ');
std::string out(in);
std::string TabsToSpaces(int tab_size, std::string in) {
size_t i = 0;
while (out.npos != (i = out.find('\t')))
out.replace(i, 1, spaces);
return out;
while ((i = in.find('\t')) != std::string::npos) {
in.replace(i, 1, tab_size, ' ');
}
return in;
}
std::string ReplaceAll(std::string result, const std::string& src, const std::string& dest) {

2
src/common/string_util.h
View file

@ -57,7 +57,7 @@ static bool TryParse(const std::string& str, N* const output) {
return false;
}
std::string TabsToSpaces(int tab_size, const std::string& in);
std::string TabsToSpaces(int tab_size, std::string in);
void SplitString(const std::string& str, char delim, std::vector<std::string>& output);